`1 + i^(2n) + i^(4n) + i^(6n)`

Select and write the correct answer from the given alternatives in each of the following: If i = sqrt(-1) and n is a positive integer, then i^n + i^(n+1) + i^(n+2) + i^(n+3) =

If n is an odd integer, i= sqrt -1 then [ (1 + i)^(6n) + (1 - i)^(6n) ] is equal to

Solve the following: Find the value of ((1 + i)^(2n) - (1 - i)^(2n)) / ((1 + omega^4 - omega^2) (1 - omega^4 + omega^2))

The simplified form i^n+i^(n+1)+i^(n+2)+i^(n+3) is

Evaluate sum_(i=1)^13( i^n + i^(n+1) ) where, n in N

The smallest positive integer n for which (1+i)^(2n) = (1-i)^(2n) is

If m, n, p, q are four consecutive integers, then the value of ( i^m + i^n + i^p + i^q ) is

By method of induction prove that 1.3 + 2.5 + 3.7 +...+ n (2n + 1) = n/6 (n + 1) (4n + 5) for all n in N

Find the value of: 1+ i^2 + i^4 + i^6 + i^8 +............+ i^20