When a coin is tossed 6 times then find the number of possible outcomes.

A fair coin is tossed 3 times. Let X be the number of heads obtained. Find E(X) and V(X).

If a coin is tossed twice and X is the number of tails, then var(X)=

Let X represent the difference between number of heads and number of tails obtaines when a coin is tossed 6 times.What are the possible values of X?

A fair coin is tossed 4 times.Let X denotes the number of heads obtained.Write down the probability distribution of X.Also find the formula for pmf of X.

IF a coin is tossed twice and X is the number of tails, then E(X)= (a) 0 (b) 1 (c) 2 (d) 3

A coin is tossed four times,then the expected value of the number of heads is………