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Pipe A can fill a cistern in 4 minutes a...

Pipe A can fill a cistern in 4 minutes and pipe B can fill it in 5 minutes. Pipe C can empty it in 2 minutes. First A and B are opened. After 2 minutes C is also opened. In how much time, the tank is emptied?

A

12 min.

B

18 min.

C

15 min.

D

20 min.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will calculate the rates of filling and emptying the cistern, determine how much water is filled in the first 2 minutes, and then find out how long it takes to empty the tank after pipe C is opened. ### Step-by-Step Solution: 1. **Determine the rates of pipes A, B, and C:** - Pipe A fills the cistern in 4 minutes, so its rate is: \[ \text{Rate of A} = \frac{20 \text{ (volume)}}{4 \text{ (time)}} = 5 \text{ units/min} \] - Pipe B fills the cistern in 5 minutes, so its rate is: \[ \text{Rate of B} = \frac{20 \text{ (volume)}}{5 \text{ (time)}} = 4 \text{ units/min} \] - Pipe C empties the cistern in 2 minutes, so its rate is: \[ \text{Rate of C} = \frac{20 \text{ (volume)}}{2 \text{ (time)}} = 10 \text{ units/min} \] 2. **Calculate the combined rate of pipes A and B when they are opened together:** - Combined rate of A and B: \[ \text{Rate of A + B} = 5 + 4 = 9 \text{ units/min} \] 3. **Calculate the volume filled in the first 2 minutes:** - Volume filled in 2 minutes: \[ \text{Volume filled} = \text{Rate of A + B} \times \text{Time} = 9 \text{ units/min} \times 2 \text{ min} = 18 \text{ units} \] 4. **Determine the net rate when pipe C is opened:** - After 2 minutes, pipe C is also opened. The net rate becomes: \[ \text{Net rate} = \text{Rate of A + B} - \text{Rate of C} = 9 - 10 = -1 \text{ unit/min} \] - The negative sign indicates that the tank is emptying at a rate of 1 unit per minute. 5. **Calculate the time taken to empty the tank:** - Since 18 units are already filled and the net rate of emptying is 1 unit/min, the time taken to empty the tank is: \[ \text{Time to empty} = \frac{\text{Volume to empty}}{\text{Net rate}} = \frac{18 \text{ units}}{1 \text{ unit/min}} = 18 \text{ minutes} \] ### Final Answer: The tank will be emptied in **18 minutes**.
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