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Three pipes A, B and C together can fill...

Three pipes A, B and C together can fill a tank in 6 hours. C is closed after 2 hours of opening. A and B can fill the remaining part of the tank in 7 hours. In how much time C alone can fill it?

A

10 hours

B

12 hours

C

8 hours

D

14 hours

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow this approach: ### Step 1: Determine the combined rate of pipes A, B, and C. Given that pipes A, B, and C together can fill the tank in 6 hours, we can find their combined rate of work. \[ \text{Rate of A + B + C} = \frac{1 \text{ tank}}{6 \text{ hours}} = \frac{1}{6} \text{ tanks/hour} \] ### Step 2: Calculate the amount of work done by A, B, and C in the first 2 hours. Since C is closed after 2 hours, we can calculate how much of the tank is filled in that time. \[ \text{Work done in 2 hours} = \text{Rate} \times \text{Time} = \frac{1}{6} \times 2 = \frac{1}{3} \text{ of the tank} \] ### Step 3: Determine the remaining work after C is closed. After 2 hours, the remaining part of the tank to be filled is: \[ \text{Remaining work} = 1 - \frac{1}{3} = \frac{2}{3} \text{ of the tank} \] ### Step 4: Find the rate of A and B together. We are told that A and B can fill the remaining part of the tank in 7 hours. Thus, their combined rate is: \[ \text{Rate of A + B} = \frac{2/3 \text{ tank}}{7 \text{ hours}} = \frac{2}{21} \text{ tanks/hour} \] ### Step 5: Relate the rates of A, B, and C. We know the rate of A + B + C is \(\frac{1}{6}\) tanks/hour and the rate of A + B is \(\frac{2}{21}\) tanks/hour. We can find the rate of C by subtracting the rate of A + B from the rate of A + B + C: \[ \text{Rate of C} = \text{Rate of A + B + C} - \text{Rate of A + B} = \frac{1}{6} - \frac{2}{21} \] ### Step 6: Find a common denominator and calculate the rate of C. The common denominator of 6 and 21 is 42. Thus, we convert the rates: \[ \frac{1}{6} = \frac{7}{42}, \quad \frac{2}{21} = \frac{4}{42} \] Now we can subtract: \[ \text{Rate of C} = \frac{7}{42} - \frac{4}{42} = \frac{3}{42} = \frac{1}{14} \text{ tanks/hour} \] ### Step 7: Calculate the time taken by C to fill the tank alone. To find the time taken by C to fill the tank alone, we use the formula: \[ \text{Time} = \frac{\text{Volume}}{\text{Rate}} = \frac{1 \text{ tank}}{\frac{1}{14} \text{ tanks/hour}} = 14 \text{ hours} \] ### Final Answer: C alone can fill the tank in **14 hours**. ---
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