Home
Class 14
MATHS
a:b:c=(1)/(3):(1)/(5):(1)/(2), a:b:c...

`a:b:c=(1)/(3):(1)/(5):(1)/(2)`, `a:b:c`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem where the ratio \( a:b:c = \frac{1}{3}:\frac{1}{5}:\frac{1}{2} \), we will follow these steps: ### Step 1: Convert the given ratios to a common form We start with the given ratios: \[ a:b:c = \frac{1}{3}:\frac{1}{5}:\frac{1}{2} \] To make calculations easier, we will find a common denominator for the fractions. The denominators are 3, 5, and 2. The least common multiple (LCM) of these numbers is 30. ### Step 2: Express each ratio in terms of the common denominator Now, we convert each fraction to have the denominator of 30: - For \( \frac{1}{3} \): \[ \frac{1}{3} = \frac{10}{30} \] - For \( \frac{1}{5} \): \[ \frac{1}{5} = \frac{6}{30} \] - For \( \frac{1}{2} \): \[ \frac{1}{2} = \frac{15}{30} \] ### Step 3: Write the ratios with the common denominator Now we can rewrite the ratios: \[ a:b:c = 10:6:15 \] ### Step 4: Simplify the ratios if necessary We can simplify the ratio \( 10:6:15 \) by finding the greatest common divisor (GCD) of the numbers. The GCD of 10, 6, and 15 is 1, so the ratio is already in its simplest form. ### Final Answer Thus, the final ratio is: \[ a:b:c = 10:6:15 \] ---
Promotional Banner

Topper's Solved these Questions

  • RATIO

    MOTHERS|Exercise Sum & Product|23 Videos
  • RATIO

    MOTHERS|Exercise Ratio Merge Tricks|15 Videos
  • RATIO

    MOTHERS|Exercise Ratio Merge Tricks|15 Videos
  • PROFIT & LOSS (PREVIOUS YEAR QUESTIONS 2018)

    MOTHERS|Exercise QUESTIONS |123 Videos
  • RATIO & PROPORTION

    MOTHERS|Exercise Multiple Choice Question|246 Videos

Similar Questions

Explore conceptually related problems

If a:b:c=2:3:4, then (1)/(a):(1)/(b):(1)/(c) is equal to (1)/(4):(1)/(3):(1)/(2) b.4:3:2 c.6:4:3 d.none of these

det[[ Prove that ,1+a,1,11,a+b,11,1,1+c]]=abc(a+(1)/(a)+(1)/(b)+(1)/(c))=abc+bc+ca+ab

Prove that: |1+a1111+b1111+c|=abc(1+(1)/(a)+(1)/(b)+(1)/(c))=abc+bc+ca+ab

(1)/(3)A=(1)/(4)B=(1)/(5)C, then A:B:C is

Prove that ,11+a,1+b,11,1,1+c]|=(abc)((1)/(a)+(1)/(b)+(1)/(c)+1)=(bc+ca+ab+abc)

If a,b,c in R^(+), then (bc)/(b+c)+(ac)/(a+c)+(ab)/(a+b) is always (a) (a) =(1)/(3)sqrt(abc)(c) =(1)/(2)sqrt(abc)

If sin^(-1)a+sin^(-1)b+sin^(-1)c=pi, then the value of ^( value of )+b sqrt((1-b^(2)))+sqrt((1-c^(2))) will be (A) 2abc(B)abc(C)(1)/(2)abc(D)(1)/(3)abc

a +b+c= 3, (1)/(a) + (1)/(b) + (1)/(c )=2 a^(2) + b^(2) + c^(2)=6 find abc=?