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A shopkeeper promise to sell his goods a...

A shopkeeper promise to sell his goods at x% loss but he uses 20% less weight than gain 20%. Find x.

A

0.08

B

0.12

C

0.11

D

0.04

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the situation described in the question. ### Step 1: Understand the Problem The shopkeeper claims to sell his goods at a loss of x%, but he uses 20% less weight, which allows him to gain a profit of 20%. We need to find the value of x. ### Step 2: Assume Values Let's assume the cost price (CP) of 100 grams of goods is 100 rupees. This makes calculations easier. ### Step 3: Calculate Selling Price (SP) at x% Loss If the shopkeeper sells at x% loss, the selling price (SP) can be calculated as: \[ SP = CP - (x\% \text{ of } CP) \] \[ SP = 100 - \frac{x}{100} \times 100 \] \[ SP = 100 - x \] ### Step 4: Determine Actual Weight Sold Since the shopkeeper uses 20% less weight, the actual weight sold is: \[ \text{Actual Weight} = 100 - 20\% \text{ of } 100 = 100 - 20 = 80 \text{ grams} \] ### Step 5: Calculate the Cost Price for Actual Weight The cost price for 80 grams (which is the actual weight sold) is: \[ \text{CP for 80 grams} = 80 \text{ grams cost } = \frac{80}{100} \times 100 = 80 \text{ rupees} \] ### Step 6: Calculate Selling Price with 20% Gain The shopkeeper gains 20% on the cost price of 80 rupees. Therefore, the selling price (SP) for 80 grams is: \[ SP = CP + (20\% \text{ of } CP) \] \[ SP = 80 + \frac{20}{100} \times 80 \] \[ SP = 80 + 16 = 96 \text{ rupees} \] ### Step 7: Set the Selling Prices Equal Now, we have two expressions for selling price: 1. From the x% loss: \( SP = 100 - x \) 2. From the 20% gain: \( SP = 96 \) Setting them equal gives: \[ 100 - x = 96 \] ### Step 8: Solve for x To find x, rearrange the equation: \[ x = 100 - 96 \] \[ x = 4 \] ### Conclusion The value of x is 4%.
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