A shopkeeper buys two cameras at the same price. He sells one camera at a profit of 18% and the other at a price of 10% less than the selling price of the first. His total profit or loss percent is :

Options

A. a)12.1% profit
B. b)12.1% loss
C. c)12.2% profit
D. d)11.1% loss

Answer

To solve the problem step by step, we will follow the given information about the shopkeeper's transactions with the cameras.

### Step 1: Define the Cost Price (CP)
Let's assume the cost price of each camera is \( CP = 100 \) (we can assume any value since they are the same).

### Step 2: Calculate the Selling Price (SP) of the First Camera
The shopkeeper sells the first camera at a profit of 18%.
- Profit = 18% of CP = \( 18\% \times 100 = 18 \)
- Selling Price of the first camera = \( CP + Profit = 100 + 18 = 118 \)

### Step 3: Calculate the Selling Price (SP) of the Second Camera
The second camera is sold at a price that is 10% less than the selling price of the first camera.
- 10% of the SP of the first camera = \( 10\% \times 118 = 11.8 \)
- Selling Price of the second camera = \( SP_{first} - 10\% \text{ of } SP_{first} = 118 - 11.8 = 106.2 \)

### Step 4: Calculate the Total Cost Price (CP) and Total Selling Price (SP)
- Total Cost Price for two cameras = \( 100 + 100 = 200 \)
- Total Selling Price for both cameras = \( SP_{first} + SP_{second} = 118 + 106.2 = 224.2 \)

### Step 5: Calculate Total Profit
- Total Profit = Total Selling Price - Total Cost Price = \( 224.2 - 200 = 24.2 \)

### Step 6: Calculate Profit Percentage
- Profit Percentage = \( \left( \frac{Total Profit}{Total CP} \right) \times 100 = \left( \frac{24.2}{200} \right) \times 100 \)
- Profit Percentage = \( 12.1\% \)

### Final Answer
The total profit percentage is \( 12.1\% \).

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