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A profit of 12% is made when a mobile ph...

A profit of 12% is made when a mobile phone is sold at P and there is 4% loss when the phone is sold at Rs Q. Then Q: Pis:

A

`4:5`

B

`3:1`

C

`1:1`

D

`6:7`

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The correct Answer is:
To solve the problem, we need to find the ratio of Q to P given the profit and loss percentages when a mobile phone is sold at these prices. ### Step-by-Step Solution: 1. **Understanding the Profit and Loss:** - When the mobile phone is sold at price P, there is a profit of 12%. - When it is sold at price Q, there is a loss of 4%. 2. **Setting Up the Equations:** - Let the cost price (CP) of the mobile phone be 100 (this is a common practice to simplify calculations). - Selling Price (SP) when sold at P: \[ P = CP + \text{Profit} = 100 + 12\% \text{ of } 100 = 100 + 12 = 112 \] - Selling Price (SP) when sold at Q: \[ Q = CP - \text{Loss} = 100 - 4\% \text{ of } 100 = 100 - 4 = 96 \] 3. **Finding the Ratio of Q to P:** - Now we need to find the ratio \( \frac{Q}{P} \): \[ \frac{Q}{P} = \frac{96}{112} \] 4. **Simplifying the Ratio:** - To simplify \( \frac{96}{112} \), we can divide both the numerator and the denominator by their greatest common divisor (GCD). - The GCD of 96 and 112 is 16. - So, we divide both by 16: \[ \frac{96 \div 16}{112 \div 16} = \frac{6}{7} \] 5. **Final Ratio:** - Therefore, the ratio \( Q : P \) is: \[ Q : P = 6 : 7 \] ### Conclusion: The ratio \( Q : P \) is \( 6 : 7 \).
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