20 kg fresh water melon contains `96%` water after sometime water remains `95%` find the present weight of water melon.

Options

A. `15` kg
B. `18` kg
C. `16` kg
D. `20` kg

Answer

To solve the problem step by step, we will follow the reasoning presented in the video transcript.

### Step-by-Step Solution:

1. **Identify the initial conditions**:
- The weight of the watermelon is 20 kg.
- The percentage of water in the watermelon is 96%.

2. **Calculate the weight of the pulp (non-water part)**:
- The percentage of pulp in the watermelon is \(100\% - 96\% = 4\%\).
- To find the weight of the pulp, we calculate:
\[ \text{Weight of pulp} = 20 \, \text{kg} \times \frac{4}{100} = 0.8 \, \text{kg} \]

3. **Determine the new conditions after some time**:
- After some time, the percentage of water in the watermelon is now 95%.
- This means the percentage of pulp has increased to \(100\% - 95\% = 5\%\).

4. **Set up the equation for the present weight of the watermelon**:
- Let the present weight of the watermelon be \(x\) kg.
- The weight of the pulp remains the same at 0.8 kg, but now it represents 5% of the total weight \(x\).
- We can set up the equation:
\[ 0.8 \, \text{kg} = x \times \frac{5}{100} \]

5. **Solve for \(x\)**:
- Rearranging the equation gives:
\[ x = \frac{0.8 \, \text{kg}}{\frac{5}{100}} = 0.8 \, \text{kg} \times \frac{100}{5} = 0.8 \, \text{kg} \times 20 = 16 \, \text{kg} \]

6. **Conclusion**:
- The present weight of the watermelon is \(16 \, \text{kg}\).

### Final Answer:
The present weight of the watermelon is **16 kg**.