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In an examination 40% of the students fa...

In an examination `40%` of the students failed in physics, `45%` of the students failed in chemistry `60%` of the students failed in biology. If `20%` of the students failed in physics and chemistry, `25%` of the students failed in chemistry and biology and `8%` of the students failed in all three subjects. Find the `%` of students who passed in all three subjects ?

A

`7%`

B

`8%`

C

`6%`

D

`9%`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will use the principle of inclusion-exclusion to find the percentage of students who passed in all three subjects. ### Step-by-Step Solution: 1. **Define the Variables**: - Let \( P \) be the percentage of students who failed in Physics = 40% - Let \( C \) be the percentage of students who failed in Chemistry = 45% - Let \( B \) be the percentage of students who failed in Biology = 60% - Let \( PC \) be the percentage of students who failed in both Physics and Chemistry = 20% - Let \( CB \) be the percentage of students who failed in both Chemistry and Biology = 25% - Let \( PB \) be the percentage of students who failed in both Physics and Biology (unknown for now) - Let \( PCB \) be the percentage of students who failed in all three subjects = 8% 2. **Use Inclusion-Exclusion Principle**: The formula to find the total percentage of students who failed in at least one subject is: \[ P + C + B - PC - CB - PB + PCB \] We need to find \( PB \) (the percentage of students who failed in both Physics and Biology). 3. **Substituting Known Values**: We know: - \( P = 40\% \) - \( C = 45\% \) - \( B = 60\% \) - \( PC = 20\% \) - \( CB = 25\% \) - \( PCB = 8\% \) Plugging these values into the inclusion-exclusion formula gives: \[ 40 + 45 + 60 - 20 - 25 - PB + 8 \] 4. **Simplifying the Equation**: Combine the known percentages: \[ 40 + 45 + 60 + 8 - 20 - 25 - PB = 108 - PB \] 5. **Setting Up the Equation**: Since the total percentage of students cannot exceed 100%, we set up the equation: \[ 108 - PB \leq 100 \] 6. **Solving for PB**: Rearranging gives: \[ PB \geq 8 \] This means at least 8% of students failed in both Physics and Biology. 7. **Finding the Percentage of Students Who Passed All Subjects**: To find the percentage of students who passed all subjects, we need to calculate: \[ \text{Percentage who passed} = 100\% - \text{Percentage who failed in at least one subject} \] Using \( PB = 8\% \) (the minimum value): \[ \text{Percentage who failed} = 108 - 8 = 100\% \] Thus, the percentage of students who passed in all three subjects is: \[ 100\% - 100\% = 0\% \] ### Conclusion: The percentage of students who passed in all three subjects is **0%**.
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