Two laborers A and B are paid a total of `Rs. 650` per day. If A is paid `160` percent of what is paid to B, how much (in Rs) is B paid ?

Options

A. `250`
B. `400`
C. `350`
D. `450`

Answer

To solve the problem, we can follow these steps:

### Step 1: Define the variables
Let the amount paid to laborer B be \( x \) Rs.

### Step 2: Express the payment to laborer A
Since A is paid 160% of what B is paid, we can express A's payment as:
\[ A = 160\% \text{ of } B = \frac{160}{100} \times x = 1.6x \]

### Step 3: Set up the equation for total payment
According to the problem, the total payment to both A and B is Rs. 650. Therefore, we can write the equation:
\[ A + B = 650 \]
Substituting the expressions for A and B, we get:
\[ 1.6x + x = 650 \]

### Step 4: Combine like terms
Combine the terms on the left side of the equation:
\[ 2.6x = 650 \]

### Step 5: Solve for x
To find the value of \( x \), divide both sides of the equation by 2.6:
\[ x = \frac{650}{2.6} \]
Calculating this gives:
\[ x = 250 \]

### Step 6: Conclusion
Thus, the amount paid to laborer B is Rs. 250.