A,B and C are three students. A got `18%` more marks than B and `12%` less than C. If B got 220 marks, then how much marks C has got ?

Options

A. `230`
B. `295`
C. `240`
D. `290`

Answer

To find out how many marks C has got, we can follow these steps:

### Step 1: Calculate A's Marks
Since B got 220 marks and A got 18% more marks than B, we can calculate A's marks using the formula for percentage increase.

\[ \text{A's Marks} = B + \left( \frac{18}{100} \times B \right) \]

Substituting B's marks:

\[ \text{A's Marks} = 220 + \left( \frac{18}{100} \times 220 \right) \]

Calculating the percentage:

\[ \frac{18}{100} \times 220 = 39.6 \]

Now, adding this to B's marks:

\[ \text{A's Marks} = 220 + 39.6 = 259.6 \]

### Step 2: Calculate C's Marks
A got 12% less marks than C. This means that C's marks can be calculated by rearranging the percentage decrease formula. If A's marks are 12% less than C's, then C's marks can be calculated as:

\[ \text{C's Marks} = \frac{\text{A's Marks}}{1 - \frac{12}{100}} \]

Substituting A's marks:

\[ \text{C's Marks} = \frac{259.6}{1 - 0.12} = \frac{259.6}{0.88} \]

Calculating C's marks:

\[ \text{C's Marks} = 295 \]

### Final Answer
C has got **295 marks**.

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