A, B and C are three students. A got `36%` less marks than B and `16%` more marks than C. If B ogt `145` marks , then what are the marks got by C ?

Options

A. `120`
B. `110`
C. `80`
D. `75`

Answer

To find the marks obtained by student C, we can follow these steps:

### Step 1: Understand the relationship between A, B, and C
- A got 36% less marks than B.
- A got 16% more marks than C.
- B's marks = 145.

### Step 2: Calculate A's marks
Since A got 36% less than B, we can express A's marks as:
\[ A = B - 36\% \text{ of } B \]
Calculating 36% of B:
\[ 36\% \text{ of } 145 = \frac{36}{100} \times 145 = 52.2 \]
Now, substituting this value back to find A's marks:
\[ A = 145 - 52.2 = 92.8 \]

### Step 3: Calculate C's marks
Since A got 16% more marks than C, we can express C's marks as:
\[ A = C + 16\% \text{ of } C \]
This can be rewritten as:
\[ A = C + 0.16C = 1.16C \]
Now, substituting A's marks:
\[ 92.8 = 1.16C \]
To find C, we rearrange the equation:
\[ C = \frac{92.8}{1.16} \]
Calculating C's marks:
\[ C = 80 \]

### Final Answer
C got **80 marks**.

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