When (1750 + 1748 + 1752 + 70 + 35) is divided by 5, the remainder obtained is ?

Options

A. 1
B. 0
C. 16
D. 2

Answer

To find the remainder when the expression \( (1750 + 1748 + 1752 + 70 + 35) \) is divided by 5, we can follow these steps:

### Step 1: Break down the expression
We have the expression:
\[ 1750 + 1748 + 1752 + 70 + 35 \]

### Step 2: Find the remainder of each term when divided by 5
Now, we will find the remainder of each individual term when divided by 5.

1. **For 1750**:
\[ 1750 \div 5 = 350 \quad \text{(exact division, remainder is 0)} \]
Remainder = 0

2. **For 1748**:
\[ 1748 \div 5 = 349.6 \quad \text{(349 full times, remainder is 3)} \]
Remainder = 3

3. **For 1752**:
\[ 1752 \div 5 = 350.4 \quad \text{(350 full times, remainder is 2)} \]
Remainder = 2

4. **For 70**:
\[ 70 \div 5 = 14 \quad \text{(exact division, remainder is 0)} \]
Remainder = 0

5. **For 35**:
\[ 35 \div 5 = 7 \quad \text{(exact division, remainder is 0)} \]
Remainder = 0

### Step 3: Sum the remainders
Now, we sum the remainders we found:
\[ 0 + 3 + 2 + 0 + 0 = 5 \]

### Step 4: Find the remainder of the sum when divided by 5
Finally, we find the remainder of this sum when divided by 5:
\[ 5 \div 5 = 1 \quad \text{(exact division, remainder is 0)} \]
Remainder = 0

### Conclusion
Thus, the remainder when \( (1750 + 1748 + 1752 + 70 + 35) \) is divided by 5 is **0**.