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When x^2 - 7x + 15 is divided by (x - 3)...

When `x^2 - 7x + 15` is divided by (x - 3), the remainder obtained is ?

A

3

B

1

C

0

D

2

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AI Generated Solution

The correct Answer is:
To find the remainder when the polynomial \( x^2 - 7x + 15 \) is divided by \( x - 3 \), we can use the Remainder Theorem. According to this theorem, the remainder of the division of a polynomial \( f(x) \) by \( x - c \) is equal to \( f(c) \). ### Step-by-Step Solution: 1. **Identify the Polynomial and the Divisor**: - The polynomial is \( f(x) = x^2 - 7x + 15 \). - The divisor is \( x - 3 \). 2. **Apply the Remainder Theorem**: - According to the Remainder Theorem, we need to evaluate \( f(3) \) because we are dividing by \( x - 3 \). 3. **Substitute \( x = 3 \) into the Polynomial**: \[ f(3) = 3^2 - 7 \cdot 3 + 15 \] 4. **Calculate \( f(3) \)**: - First, calculate \( 3^2 \): \[ 3^2 = 9 \] - Next, calculate \( -7 \cdot 3 \): \[ -7 \cdot 3 = -21 \] - Now substitute these values into the equation: \[ f(3) = 9 - 21 + 15 \] - Combine the terms: \[ 9 - 21 = -12 \] \[ -12 + 15 = 3 \] 5. **Conclusion**: - The remainder when \( x^2 - 7x + 15 \) is divided by \( x - 3 \) is \( 3 \). ### Final Answer: The remainder is \( 3 \).
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  2. If (x + 1) and (x - 1) are the factors of polynomial ax^3 + bx^2 + 3x ...

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  3. When x^2 - 7x + 15 is divided by (x - 3), the remainder obtained is ?

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