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When 1234 .......41 digits, is divided b...

When 1234 .......41 digits, is divided by 8, the remainder obtained is ?

A

1

B

2

C

3

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To find the remainder when the number formed by writing the digits from 1 to 41 (i.e., 123456789101112...3940) is divided by 8, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Last Three Digits**: The rule for divisibility by 8 states that we only need to consider the last three digits of the number. The last three digits of our number (which is formed by writing the digits from 1 to 41) are "041". 2. **Convert the Last Three Digits to a Number**: The last three digits "041" can be treated as the number 41. 3. **Divide by 8**: Now, we will divide 41 by 8 to find the remainder. \[ 41 \div 8 = 5 \quad \text{(since } 8 \times 5 = 40\text{)} \] The remainder can be calculated as: \[ 41 - 40 = 1 \] 4. **Conclusion**: Therefore, the remainder when the entire number is divided by 8 is 1. ### Final Answer: The remainder obtained when the number is divided by 8 is **1**.
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MOTHERS-NUMBER SYSTEM-O
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  12. When (32^32)^32 is divided by 9, the remainder obtained is ?

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  13. (32^34)^35 divided by 7, the reamainder obtained is ?

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  14. When 333^555 + 555^333 is divided by 8, the remainder obtained is ?

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