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When (10^10+10^100+10^1000+........+10^1...

When `(10^10+10^100+10^1000+........+10^10000000000)` is divided by 7, then the remainder is?

A

1

B

5

C

2

D

3

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the remainder when \( (10^{10} + 10^{100} + 10^{1000} + \ldots + 10^{10000000000}) \) is divided by 7, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Series**: The expression consists of a series of terms where the exponent of 10 increases by a factor of 10 each time. The series can be expressed as: \[ S = 10^{10} + 10^{100} + 10^{1000} + \ldots + 10^{10000000000} \] 2. **Determine the Number of Terms**: The exponents are \( 10, 100, 1000, \ldots, 10^{10} \). The last term has \( 10^{10} \) which means there are 10 terms in total. 3. **Find the Remainder of Each Term Modulo 7**: We need to find \( 10^n \mod 7 \) for each term: - First, calculate \( 10 \mod 7 \): \[ 10 \equiv 3 \mod 7 \] - Now, we will find the powers of 3 modulo 7: - \( 3^1 \equiv 3 \mod 7 \) - \( 3^2 \equiv 9 \equiv 2 \mod 7 \) - \( 3^3 \equiv 6 \mod 7 \) - \( 3^4 \equiv 18 \equiv 4 \mod 7 \) - \( 3^5 \equiv 12 \equiv 5 \mod 7 \) - \( 3^6 \equiv 15 \equiv 1 \mod 7 \) The powers of 3 repeat every 6 terms. Therefore, we can find \( 10^n \mod 7 \) by determining \( n \mod 6 \). 4. **Calculate \( n \mod 6 \)** for each exponent: - For \( n = 10 \): \[ 10 \mod 6 = 4 \quad \Rightarrow \quad 10^{10} \equiv 3^4 \equiv 4 \mod 7 \] - For \( n = 100 \): \[ 100 \mod 6 = 4 \quad \Rightarrow \quad 10^{100} \equiv 3^4 \equiv 4 \mod 7 \] - For \( n = 1000 \): \[ 1000 \mod 6 = 4 \quad \Rightarrow \quad 10^{1000} \equiv 3^4 \equiv 4 \mod 7 \] - This pattern continues for all terms since all \( n \) values (10, 100, 1000, ..., \( 10^{10} \)) give \( n \mod 6 = 4 \). 5. **Sum the Remainders**: Since each term contributes a remainder of 4: \[ S \equiv 4 + 4 + 4 + \ldots + 4 \quad (\text{10 terms}) \equiv 10 \times 4 = 40 \mod 7 \] 6. **Calculate \( 40 \mod 7 \)**: \[ 40 \div 7 = 5 \quad \text{remainder } 5 \] Thus, \[ 40 \equiv 5 \mod 7 \] ### Final Answer: The remainder when \( (10^{10} + 10^{100} + 10^{1000} + \ldots + 10^{10000000000}) \) is divided by 7 is **5**.
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