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If a, b are rational numbers and asqrtbs...

If a, b are rational numbers and `asqrtbsqrt3=sqrt(98)+sqrt(108)-sqrt(48)-sqrt(72)`, then the values of a and b are?

A

1,2

B

1,3

C

2,1

D

2,3

Text Solution

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The correct Answer is:
To solve the equation \( a \sqrt{b} \sqrt{3} = \sqrt{98} + \sqrt{108} - \sqrt{48} - \sqrt{72} \), we will simplify the right-hand side step by step and then compare coefficients to find the values of \( a \) and \( b \). ### Step 1: Simplify \( \sqrt{98} \) \[ \sqrt{98} = \sqrt{49 \times 2} = \sqrt{49} \cdot \sqrt{2} = 7\sqrt{2} \] **Hint:** Factor the number under the square root to find perfect squares. ### Step 2: Simplify \( \sqrt{108} \) \[ \sqrt{108} = \sqrt{36 \times 3} = \sqrt{36} \cdot \sqrt{3} = 6\sqrt{3} \] **Hint:** Look for the largest perfect square that divides the number. ### Step 3: Simplify \( \sqrt{48} \) \[ \sqrt{48} = \sqrt{16 \times 3} = \sqrt{16} \cdot \sqrt{3} = 4\sqrt{3} \] **Hint:** Again, factor to find perfect squares. ### Step 4: Simplify \( \sqrt{72} \) \[ \sqrt{72} = \sqrt{36 \times 2} = \sqrt{36} \cdot \sqrt{2} = 6\sqrt{2} \] **Hint:** Use the same method of factoring to simplify. ### Step 5: Combine the simplified terms Now substitute back into the equation: \[ \sqrt{98} + \sqrt{108} - \sqrt{48} - \sqrt{72} = 7\sqrt{2} + 6\sqrt{3} - 4\sqrt{3} - 6\sqrt{2} \] Combine like terms: \[ (7\sqrt{2} - 6\sqrt{2}) + (6\sqrt{3} - 4\sqrt{3}) = 1\sqrt{2} + 2\sqrt{3} \] ### Step 6: Set the equation equal to \( a \sqrt{b} \sqrt{3} \) Now we have: \[ a \sqrt{b} \sqrt{3} = 1\sqrt{2} + 2\sqrt{3} \] ### Step 7: Compare coefficients From the equation \( a \sqrt{b} \sqrt{3} = 1\sqrt{2} + 2\sqrt{3} \), we can see that: - The coefficient of \( \sqrt{2} \) is \( 1 \) - The coefficient of \( \sqrt{3} \) is \( 2 \) This implies: - \( a \sqrt{b} = 2 \) (coefficient of \( \sqrt{3} \)) - \( a \) must be \( 1 \) (coefficient of \( \sqrt{2} \)) ### Step 8: Solve for \( a \) and \( b \) From \( a = 1 \): \[ 1 \cdot \sqrt{b} = 2 \Rightarrow \sqrt{b} = 2 \Rightarrow b = 4 \] ### Final Values Thus, the values of \( a \) and \( b \) are: \[ a = 1, \quad b = 4 \] ### Summary The final answer is: - \( a = 1 \) - \( b = 4 \)
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