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If root(3)(a)=root(3)(26)+root(3)(7)+roo...

If `root(3)(a)=root(3)(26)+root(3)(7)+root(3)(63)`, then-

A

alt 729 but agt 216

B

alt 216

C

agt 729

D

agt 729

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The correct Answer is:
To solve the equation \( \sqrt[3]{a} = \sqrt[3]{26} + \sqrt[3]{7} + \sqrt[3]{63} \), we will follow these steps: ### Step 1: Simplify the equation We know that \( \sqrt[3]{63} \) can be simplified. Since \( 63 = 3^2 \times 7 \), we can rewrite it as: \[ \sqrt[3]{63} = \sqrt[3]{3^2 \times 7} = \sqrt[3]{9} \cdot \sqrt[3]{7} \] ### Step 2: Substitute back into the equation Now, substituting this back into the original equation gives us: \[ \sqrt[3]{a} = \sqrt[3]{26} + \sqrt[3]{7} + \sqrt[3]{9} \cdot \sqrt[3]{7} \] ### Step 3: Combine like terms Notice that \( \sqrt[3]{7} \) is common in two terms. We can factor it out: \[ \sqrt[3]{a} = \sqrt[3]{26} + \sqrt[3]{7}(1 + \sqrt[3]{9}) \] ### Step 4: Calculate the approximate values Now we can calculate approximate values: - \( \sqrt[3]{26} \approx 2.96 \) - \( \sqrt[3]{7} \approx 1.91 \) - \( \sqrt[3]{9} \approx 2.08 \) Calculating \( 1 + \sqrt[3]{9} \): \[ 1 + \sqrt[3]{9} \approx 1 + 2.08 = 3.08 \] Now substituting these values back: \[ \sqrt[3]{a} \approx 2.96 + 1.91 \cdot 3.08 \] Calculating \( 1.91 \cdot 3.08 \): \[ 1.91 \cdot 3.08 \approx 5.88 \] Thus, \[ \sqrt[3]{a} \approx 2.96 + 5.88 \approx 8.84 \] ### Step 5: Cube both sides to find \( a \) Now we cube both sides to find \( a \): \[ a \approx (8.84)^3 \] Calculating \( (8.84)^3 \): \[ (8.84)^3 \approx 693.5 \] ### Step 6: Conclusion Thus, we can conclude that: \[ a \approx 693.5 \]
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