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3root(3)(32)-5root(3)(4)+root(3)(500) is...

`3root(3)(32)-5root(3)(4)+root(3)(500)` is equal to

A

`4root(3)(6)`

B

`3sqrt(24)`

C

`6root(3)(4)`

D

916

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( 3 \sqrt[3]{32} - 5 \sqrt[3]{4} + \sqrt[3]{500} \), we will simplify each term step by step. ### Step 1: Simplify \( \sqrt[3]{32} \) We can express \( 32 \) as \( 8 \times 4 \): \[ \sqrt[3]{32} = \sqrt[3]{8 \times 4} = \sqrt[3]{8} \times \sqrt[3]{4} \] Since \( \sqrt[3]{8} = 2 \): \[ \sqrt[3]{32} = 2 \sqrt[3]{4} \] ### Step 2: Substitute back into the expression Now substitute \( \sqrt[3]{32} \) back into the original expression: \[ 3 \sqrt[3]{32} = 3 \times 2 \sqrt[3]{4} = 6 \sqrt[3]{4} \] So, we have: \[ 6 \sqrt[3]{4} - 5 \sqrt[3]{4} + \sqrt[3]{500} \] ### Step 3: Combine like terms Now combine the terms involving \( \sqrt[3]{4} \): \[ (6 - 5) \sqrt[3]{4} + \sqrt[3]{500} = 1 \sqrt[3]{4} + \sqrt[3]{500} = \sqrt[3]{4} + \sqrt[3]{500} \] ### Step 4: Simplify \( \sqrt[3]{500} \) We can express \( 500 \) as \( 125 \times 4 \): \[ \sqrt[3]{500} = \sqrt[3]{125 \times 4} = \sqrt[3]{125} \times \sqrt[3]{4} \] Since \( \sqrt[3]{125} = 5 \): \[ \sqrt[3]{500} = 5 \sqrt[3]{4} \] ### Step 5: Substitute back into the expression Now substitute \( \sqrt[3]{500} \) back into the expression: \[ \sqrt[3]{4} + 5 \sqrt[3]{4} = (1 + 5) \sqrt[3]{4} = 6 \sqrt[3]{4} \] ### Final Answer Thus, the expression \( 3 \sqrt[3]{32} - 5 \sqrt[3]{4} + \sqrt[3]{500} \) simplifies to: \[ \boxed{6 \sqrt[3]{4}} \]
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MOTHERS-NUMBER SYSTEM-O
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