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Which no. is the greatest number from th...

Which no. is the greatest number from the following:
`root(3)(4),root(6)(15),root(4)(6)` and `root(12)(245)`

A

`root(3)(4)`

B

`root(4)(6)`

C

`root(6)(15)`

D

`root(12)(245)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the greatest number among the given roots, we need to evaluate each expression: \( \sqrt[3]{4} \), \( \sqrt[6]{15} \), \( \sqrt[4]{6} \), and \( \sqrt[12]{245} \). ### Step-by-Step Solution: 1. **Rewrite the Roots in Exponential Form**: - \( \sqrt[3]{4} = 4^{1/3} \) - \( \sqrt[6]{15} = 15^{1/6} \) - \( \sqrt[4]{6} = 6^{1/4} \) - \( \sqrt[12]{245} = 245^{1/12} \) 2. **Find the Least Common Multiple (LCM) of the Denominators**: - The denominators are 3, 6, 4, and 12. - The LCM of these numbers is 12. 3. **Express Each Root with a Common Denominator**: - Rewrite each expression using the LCM: - \( 4^{1/3} = 4^{4/12} \) - \( 15^{1/6} = 15^{2/12} \) - \( 6^{1/4} = 6^{3/12} \) - \( 245^{1/12} = 245^{1/12} \) 4. **Combine the Expressions Under the Same Root**: - Now we can express them all as 12th roots: - \( \sqrt[12]{4^4} = \sqrt[12]{256} \) - \( \sqrt[12]{15^2} = \sqrt[12]{225} \) - \( \sqrt[12]{6^3} = \sqrt[12]{216} \) - \( \sqrt[12]{245} = \sqrt[12]{245} \) 5. **Calculate the Values**: - \( 256 \) (from \( 4^4 \)) - \( 225 \) (from \( 15^2 \)) - \( 216 \) (from \( 6^3 \)) - \( 245 \) (from \( 245 \)) 6. **Compare the Values**: - Now we compare the values: - \( 256 > 225 > 216 > 245 \) 7. **Identify the Greatest Value**: - The greatest value is \( 256 \), which corresponds to \( \sqrt[3]{4} \). ### Conclusion: The greatest number among the given options is \( \sqrt[3]{4} \).
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