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1/3+1/15+1/35+1/63+1/99+1/143=?...

`1/3+1/15+1/35+1/63+1/99+1/143=?`

A

a)`6/13`

B

b)`5/7`

C

c)`6/11`

D

d)`11/6`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem \( \frac{1}{3} + \frac{1}{15} + \frac{1}{35} + \frac{1}{63} + \frac{1}{99} + \frac{1}{143} \), we can follow a systematic approach. ### Step-by-Step Solution: 1. **Identify the Denominators**: The denominators are \( 3, 15, 35, 63, 99, \) and \( 143 \). 2. **Factor the Denominators**: - \( 3 = 1 \times 3 \) - \( 15 = 3 \times 5 \) - \( 35 = 5 \times 7 \) - \( 63 = 7 \times 9 \) - \( 99 = 9 \times 11 \) - \( 143 = 11 \times 13 \) 3. **Observe the Pattern**: The denominators can be expressed in terms of consecutive odd numbers: - \( 3 = 1 \times 3 \) - \( 15 = 3 \times 5 \) - \( 35 = 5 \times 7 \) - \( 63 = 7 \times 9 \) - \( 99 = 9 \times 11 \) - \( 143 = 11 \times 13 \) 4. **Identify the Formula**: We can use the formula for the sum of fractions of this type: \[ \text{Sum} = \frac{1}{\text{difference of factors}} \times \left( \text{highest factor} - \text{lowest factor} \right) \] Here, the difference of factors is \( 2 \) (since the difference between consecutive odd numbers is \( 2 \)), the lowest factor is \( 3 \), and the highest factor is \( 13 \). 5. **Apply the Formula**: \[ \text{Sum} = \frac{1}{2} \times (13 - 1) = \frac{1}{2} \times 12 = \frac{12}{2} = 6 \] 6. **Final Calculation**: Since we need to express the answer in terms of the sum of the fractions: \[ \text{Final Answer} = \frac{6}{13} \] ### Conclusion: Thus, the result of \( \frac{1}{3} + \frac{1}{15} + \frac{1}{35} + \frac{1}{63} + \frac{1}{99} + \frac{1}{143} \) is \( \frac{6}{13} \).
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