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The simplification of (1.bar3xx1.bar3xx1...

The simplification of `(1.bar3xx1.bar3xx1.bar3-1)/(1.bar3xx1.bar3+1.bar3+1)` is

A

`1/3`

B

`1(1)/3`

C

`37/91`

D

`27/91`

Text Solution

AI Generated Solution

The correct Answer is:
To simplify the expression \((1.\overline{3} \times 1.\overline{3} \times 1.\overline{3} - 1) / (1.\overline{3} \times 1.\overline{3} + 1.\overline{3} + 1)\), we will follow these steps: ### Step 1: Convert \(1.\overline{3}\) to a Fraction Let \(x = 1.\overline{3}\). Then, we can express \(x\) as: \[ x = 1.3333\ldots \] Multiplying both sides by 10: \[ 10x = 13.3333\ldots \] Now, we can set up the equation: \[ 10x - x = 13.3333\ldots - 1.3333\ldots \] This simplifies to: \[ 9x = 12 \] Thus, we find: \[ x = \frac{12}{9} = \frac{4}{3} \] ### Step 2: Substitute \(1.\overline{3}\) with \(\frac{4}{3}\) Now, we substitute \(1.\overline{3}\) with \(\frac{4}{3}\) in the original expression: \[ \frac{\left(\frac{4}{3} \times \frac{4}{3} \times \frac{4}{3}\right) - 1}{\left(\frac{4}{3} \times \frac{4}{3}\right) + \frac{4}{3} + 1} \] ### Step 3: Simplify the Numerator Calculating the numerator: \[ \frac{4}{3} \times \frac{4}{3} \times \frac{4}{3} = \frac{64}{27} \] Thus, the numerator becomes: \[ \frac{64}{27} - 1 = \frac{64}{27} - \frac{27}{27} = \frac{64 - 27}{27} = \frac{37}{27} \] ### Step 4: Simplify the Denominator Calculating the denominator: \[ \frac{4}{3} \times \frac{4}{3} = \frac{16}{9} \] Now adding \(\frac{4}{3}\) and \(1\): \[ \frac{4}{3} + 1 = \frac{4}{3} + \frac{3}{3} = \frac{7}{3} \] Now, we find the common denominator for \(\frac{16}{9}\) and \(\frac{7}{3}\): \[ \frac{7}{3} = \frac{21}{9} \] Thus, the denominator becomes: \[ \frac{16}{9} + \frac{21}{9} = \frac{37}{9} \] ### Step 5: Combine the Results Now we can combine the results: \[ \frac{\frac{37}{27}}{\frac{37}{9}} = \frac{37}{27} \times \frac{9}{37} = \frac{9}{27} = \frac{1}{3} \] ### Final Answer Thus, the simplification of the expression is: \[ \frac{1}{3} \]
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