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(1(1)/2+11(1)/2+111(1)/2+1111(1)/2) is e...

`(1(1)/2+11(1)/2+111(1)/2+1111(1)/2)` is equal to

A

1236

B

`1234(1)/2`

C

618

D

617

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( (1(1)/2 + 11(1)/2 + 111(1)/2 + 1111(1)/2) \), we can break it down step by step. ### Step 1: Rewrite the expression The expression can be rewritten as: \[ \frac{1}{2} + \frac{11}{2} + \frac{111}{2} + \frac{1111}{2} \] ### Step 2: Factor out \(\frac{1}{2}\) Since \(\frac{1}{2}\) is common in all terms, we can factor it out: \[ \frac{1}{2} \left( 1 + 11 + 111 + 1111 \right) \] ### Step 3: Calculate the sum inside the parentheses Now, we need to calculate \( 1 + 11 + 111 + 1111 \): - \( 1 + 11 = 12 \) - \( 12 + 111 = 123 \) - \( 123 + 1111 = 1234 \) So, we have: \[ 1 + 11 + 111 + 1111 = 1234 \] ### Step 4: Substitute back into the expression Now substitute back into the expression: \[ \frac{1}{2} \times 1234 \] ### Step 5: Multiply to find the final answer Now, calculate: \[ \frac{1234}{2} = 617 \] Thus, the final answer is: \[ \boxed{617} \] ---
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