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The value of (0.333 ...... xx 0.444 .......

The value of (0.333 ...... `xx` 0.444 .... ) is

A

0.148148 ...

B

0.777 ...

C

0.1212 ....

D

1.333 ... .

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The correct Answer is:
To find the value of \(0.333...\) multiplied by \(0.444...\), we can follow these steps: ### Step 1: Convert the repeating decimals to fractions The first number, \(0.333...\), can be expressed as a fraction. We know that: \[ 0.333... = \frac{3}{9} = \frac{1}{3} \] The second number, \(0.444...\), can also be expressed as a fraction: \[ 0.444... = \frac{4}{9} \] ### Step 2: Multiply the fractions Now, we need to multiply the two fractions we found: \[ \frac{1}{3} \times \frac{4}{9} = \frac{1 \times 4}{3 \times 9} = \frac{4}{27} \] ### Step 3: Final Result Thus, the value of \(0.333... \times 0.444...\) is: \[ \frac{4}{27} \] ### Step 4: Convert the fraction to decimal (if needed) To express \(\frac{4}{27}\) as a decimal, we can perform the division: \[ 4 \div 27 \approx 0.148148... \] This shows that \(\frac{4}{27} \approx 0.148148...\), which is a repeating decimal. ### Summary The value of \(0.333... \times 0.444...\) is \(\frac{4}{27}\) or approximately \(0.148148...\). ---
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MOTHERS-NUMBER SYSTEM-O
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  3. The value of (0.333 ...... xx 0.444 .... ) is

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  4. 1/20+1/30+1/42+1/56+1/72+1/90+1/110+1/132=?

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  5. Find the square root of ((0.064-0.008)(0.16-0.04))/((0.16+0.08+0.04)(0...

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  9. Which sequence is in desending order:

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  10. The value of (0.34bar(68)+.17bar(32)) is

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  13. If a/3=b/2 then find the value of (2a+3b)/(3a-2b)

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  14. (11^3 + 12^3 + 13^3 + ...... + 30^3) = ?

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  16. Find the biggest number among the following- 0.9,0.bar9,0.0bar9,0.ba...

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  17. What is the descending order of 11/17,7/11,8/15,5/9?

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  18. The value of (0.2xx0.2xx0.2+0.3xx0.3xx0.3)/(0.4xx0.4xx0.4+0.6xx0.6xx0....

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