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The value of (0.2xx0.2xx0.2+0.3xx0.3xx0....

The value of `(0.2xx0.2xx0.2+0.3xx0.3xx0.3)/(0.4xx0.4xx0.4+0.6xx0.6xx0.6)` is

A

`1/8`

B

`1/6`

C

`1/4`

D

`1/5`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \((0.2 \times 0.2 \times 0.2 + 0.3 \times 0.3 \times 0.3) / (0.4 \times 0.4 \times 0.4 + 0.6 \times 0.6 \times 0.6)\), we can follow these steps: ### Step 1: Simplify the Numerator The numerator is \(0.2 \times 0.2 \times 0.2 + 0.3 \times 0.3 \times 0.3\). Calculating each term: - \(0.2 \times 0.2 \times 0.2 = 0.2^3 = 0.008\) - \(0.3 \times 0.3 \times 0.3 = 0.3^3 = 0.027\) Now, add these two results together: \[ 0.008 + 0.027 = 0.035 \] ### Step 2: Simplify the Denominator The denominator is \(0.4 \times 0.4 \times 0.4 + 0.6 \times 0.6 \times 0.6\). Calculating each term: - \(0.4 \times 0.4 \times 0.4 = 0.4^3 = 0.064\) - \(0.6 \times 0.6 \times 0.6 = 0.6^3 = 0.216\) Now, add these two results together: \[ 0.064 + 0.216 = 0.280 \] ### Step 3: Divide the Numerator by the Denominator Now we have: \[ \frac{0.035}{0.280} \] To simplify this fraction, we can divide both the numerator and the denominator by \(0.035\): \[ \frac{0.035 \div 0.035}{0.280 \div 0.035} = \frac{1}{8} \] ### Final Answer Thus, the value of the expression is: \[ \frac{1}{8} \] ---
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