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Which one of the following is correct ? ...

Which one of the following is correct ?
(i) `13^31gt31^13`
(ii) `10^100lt100^10`
(iii) `23^2lt32^2`

A

a)(i) and (ii)

B

b)(i) and (iii)

C

c)(ii) and (iii)

D

d)(i) only

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze each of the three statements given and determine which one is correct. ### Step 1: Analyze the first statement **Statement (i):** \( 13^{31} > 31^{13} \) To compare these two expressions, we can take the logarithm of both sides: \[ \log(13^{31}) > \log(31^{13}) \] Using the property of logarithms, we can simplify this: \[ 31 \cdot \log(13) > 13 \cdot \log(31) \] Now, we can calculate the values of \( \log(13) \) and \( \log(31) \): - \( \log(13) \approx 1.113943 \) - \( \log(31) \approx 1.491654 \) Now substituting these values: \[ 31 \cdot 1.113943 > 13 \cdot 1.491654 \] Calculating both sides: - Left side: \( 31 \cdot 1.113943 \approx 34.525 \) - Right side: \( 13 \cdot 1.491654 \approx 19.391 \) Since \( 34.525 > 19.391 \), the first statement is **true**. ### Step 2: Analyze the second statement **Statement (ii):** \( 10^{100} < 100^{10} \) We can rewrite \( 100 \) as \( 10^2 \): \[ 100^{10} = (10^2)^{10} = 10^{20} \] Now we compare: \[ 10^{100} < 10^{20} \] This is incorrect because \( 10^{100} \) is much larger than \( 10^{20} \). Therefore, the second statement is **false**. ### Step 3: Analyze the third statement **Statement (iii):** \( 23^2 < 32^2 \) Calculating both sides: - \( 23^2 = 529 \) - \( 32^2 = 1024 \) Now we compare: \[ 529 < 1024 \] This statement is **true**. ### Conclusion From our analysis: - Statement (i) is true. - Statement (ii) is false. - Statement (iii) is true. Thus, the correct statements are (i) and (iii). ### Final Answer The correct options are (i) \( 13^{31} > 31^{13} \) and (iii) \( 23^2 < 32^2 \). ---
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