In a quadrilateral ABCD angle bisector o...

In a quadrilateral ABCD angle bisector of `angleB and angleD` are meeting at point P and Q respectively on extended sides of CD and AB. Then how `angleP and angleQ, angleABC and angleaADC` are related.

A

`angleP+angleQ=1//2(angleABC+angleADC)`

B

`angleP+angleQ=(angleABC+angleADC)`

C

`(angleP+angleQ)=2(angleABC+angleADC)`

D

`(angleP+angleQ)=(angleABC+angleADC)`

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