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ABC is a cyclic triangle and the bisecto...

ABC is a cyclic triangle and the bisectors of `angle BAC, angle ABC and angle BCA` meet the circle at P,Q and R respectively. Then the angle `angle RQP` is:

A

`90^(@)-(angleA)/(2)`

B

`90^(@)+(angleB)/(2)`

C

`90^(@)-(angleB)/(2)`

D

`90^(@)+(angleC)/(2)`

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