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ABCD is a rhombus, AB is extended to F a...

ABCD is a rhombus, AB is extended to F and BA to E such that AB = AE = BF then what is the result?

A

`ED gt CF`

B

`ED_|_CF`

C

`ED^(2)+CF^(2)=EF^(2)`

D

`ED||CF`

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