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An isosceles triangle ABC is right angle...

An isosceles triangle ABC is right angled at B.D is a point inside the triangle ABC. P and Q are the feet of the perpendiculars drawn from D on the sides AB and AC respectively of `Delta ABC`. If AP = a cm, AQ = b cm and `angle BAD= 15^(@), sin 75^(@)=`

A

`(2b)/(sqrt(3)a)`

B

`(a)/(2b)`

C

`(sqrt(3)a)/(2b)`

D

`(2a)/(sqrt(3)b)`

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