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DeltaABC is an acute angle triangle. AD ...

`DeltaABC` is an acute angle triangle. AD is perpendiculra on BC and DB = 3 CD. Find `BC^(2)`-

A

`2(AB^(2)-AC^(2))`

B

`2(AD^(2)+BD^(2))`

C

`2(AD^(2)-BD^(2))`

D

`AB^(2)-AC^(2)`

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