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What is the difference (in ₹) between the com pound interests on ₹ 12,500 for 1 year at 8% per annum compounded yearly and halfyearly?

A

A. 16

B

B. 25

C

C. 20

D

C. 40

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The correct Answer is:
To find the difference in compound interest on ₹12,500 for 1 year at an interest rate of 8% per annum compounded yearly and half-yearly, we will follow these steps: ### Step 1: Calculate Compound Interest Compounded Yearly The formula for compound interest is: \[ A = P \left(1 + \frac{r}{100}\right)^n \] Where: - \(A\) = Total amount after time \(n\) - \(P\) = Principal amount (initial investment) - \(r\) = Rate of interest per annum - \(n\) = Number of years For yearly compounding: - \(P = 12,500\) - \(r = 8\%\) - \(n = 1\) Substituting the values: \[ A = 12500 \left(1 + \frac{8}{100}\right)^1 \] \[ A = 12500 \left(1 + 0.08\right) \] \[ A = 12500 \times 1.08 = 13500 \] Now, the compound interest (CI) for yearly compounding is: \[ CI_{yearly} = A - P = 13500 - 12500 = 1000 \] ### Step 2: Calculate Compound Interest Compounded Half-Yearly For half-yearly compounding, the formula remains the same, but the rate and time period change: - The rate per half-year = \(\frac{r}{2} = \frac{8}{2} = 4\%\) - The number of compounding periods in 1 year = 2 Substituting the values: \[ A = 12500 \left(1 + \frac{4}{100}\right)^2 \] \[ A = 12500 \left(1 + 0.04\right)^2 \] \[ A = 12500 \left(1.04\right)^2 \] Calculating \(1.04^2\): \[ 1.04^2 = 1.0816 \] Now substituting back: \[ A = 12500 \times 1.0816 = 13520 \] Now, the compound interest (CI) for half-yearly compounding is: \[ CI_{half-yearly} = A - P = 13520 - 12500 = 1020 \] ### Step 3: Calculate the Difference in Compound Interests Now, we find the difference between the two compound interests: \[ \text{Difference} = CI_{half-yearly} - CI_{yearly} = 1020 - 1000 = 20 \] ### Final Answer The difference in compound interests is ₹20. ---
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