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If the difference between the CI and SI ...

If the difference between the CI and SI on some amount is 170 at the rate of `9 (1)/(11)%` interest for 3 years then find the amount?

A

₹ 6655

B

₹6556

C

₹ 5665

D

₹ 5566

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the mathematical principles of compound interest (CI) and simple interest (SI). ### Step-by-Step Solution: 1. **Identify the Given Information**: - Difference between CI and SI: \( CI - SI = 170 \) - Rate of interest: \( R = 9 \frac{1}{11}\% = \frac{100}{11}\% \) - Time period: \( T = 3 \) years 2. **Convert the Rate of Interest**: - Convert \( R \) into a decimal for calculations: \[ R = \frac{100}{11} = 9.0909\% \] 3. **Calculate Simple Interest (SI)**: - The formula for SI is: \[ SI = \frac{P \times R \times T}{100} \] - Substituting the values: \[ SI = \frac{P \times \frac{100}{11} \times 3}{100} = \frac{3P}{11} \] 4. **Calculate Compound Interest (CI)**: - The formula for CI is: \[ CI = P \left(1 + \frac{R}{100}\right)^T - P \] - Substituting the values: \[ CI = P \left(1 + \frac{100}{11 \times 100}\right)^3 - P = P \left(1 + \frac{1}{11}\right)^3 - P \] - Simplifying: \[ CI = P \left(\frac{12}{11}\right)^3 - P \] - Expanding \( \left(\frac{12}{11}\right)^3 \): \[ \left(\frac{12}{11}\right)^3 = \frac{1728}{1331} \] - Therefore: \[ CI = P \left(\frac{1728}{1331} - 1\right) = P \left(\frac{1728 - 1331}{1331}\right) = P \left(\frac{397}{1331}\right) \] 5. **Set Up the Equation**: - From the information given: \[ CI - SI = 170 \] - Substitute the expressions for CI and SI: \[ P \left(\frac{397}{1331}\right) - \frac{3P}{11} = 170 \] 6. **Find a Common Denominator**: - The common denominator for \( 1331 \) and \( 11 \) is \( 1331 \): \[ \frac{3P}{11} = \frac{3P \times 121}{1331} = \frac{363P}{1331} \] - Now, the equation becomes: \[ P \left(\frac{397}{1331} - \frac{363}{1331}\right) = 170 \] - Simplifying: \[ P \left(\frac{34}{1331}\right) = 170 \] 7. **Solve for P**: - Multiply both sides by \( 1331 \): \[ 34P = 170 \times 1331 \] - Calculate \( 170 \times 1331 = 226270 \): \[ P = \frac{226270}{34} = 6655 \] 8. **Final Answer**: - The principal amount \( P \) is \( 6655 \).
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