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An investor invested his saving in the s...

An investor invested his saving in the stock market. The value of his investments increased by 12% and 9% in the first year and the second year respectively. If the value of his investments after two years became Rs 97,664 then how much had he invested (in Rs)?

A

81000

B

75000

C

80000

D

72000

Text Solution

AI Generated Solution

The correct Answer is:
To find out how much the investor initially invested, we can use the concept of compound interest. Here’s the step-by-step solution: ### Step 1: Define the initial investment Let the initial investment be Rs X. ### Step 2: Calculate the value after the first year The investment increases by 12% in the first year. Therefore, the value after the first year can be calculated as: \[ \text{Value after 1st year} = X + (12\% \text{ of } X) = X \times \left(1 + \frac{12}{100}\right) = X \times \frac{112}{100} = X \times 1.12 \] ### Step 3: Calculate the value after the second year In the second year, the investment increases by 9%. Thus, the value after the second year can be calculated as: \[ \text{Value after 2nd year} = \text{Value after 1st year} + (9\% \text{ of Value after 1st year}) = (X \times 1.12) \times \left(1 + \frac{9}{100}\right) = (X \times 1.12) \times \frac{109}{100} \] ### Step 4: Set up the equation According to the problem, the value of the investment after 2 years is Rs 97,664. Therefore, we can set up the equation: \[ (X \times 1.12) \times \frac{109}{100} = 97,664 \] ### Step 5: Simplify the equation Now, we can simplify the left side: \[ X \times 1.12 \times 1.09 = 97,664 \] Calculating \(1.12 \times 1.09\): \[ 1.12 \times 1.09 = 1.2208 \] So, we have: \[ X \times 1.2208 = 97,664 \] ### Step 6: Solve for X To find X, divide both sides by 1.2208: \[ X = \frac{97,664}{1.2208} \] Calculating the right side: \[ X = 80,000 \] ### Conclusion The initial investment made by the investor is Rs 80,000. ---
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