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The difference between the simple intere...

The difference between the simple interest on a certain sum at the rate of 10% per annum for 2 years and the compound interest on the same sum, rate and time is ₹ 124.05. If the compound interest is semi-annually. The sum is

A

₹ 5,000

B

₹ 10,000

C

₹ 12,000

D

₹ 8,000

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The correct Answer is:
To solve the problem step by step, we will follow the outlined approach from the video transcript. ### Step 1: Define the Variables Let the principal amount be \( P \). ### Step 2: Calculate Simple Interest (SI) The formula for Simple Interest is given by: \[ SI = \frac{P \times R \times T}{100} \] Where: - \( R = 10\% \) (rate of interest) - \( T = 2 \) years Substituting the values: \[ SI = \frac{P \times 10 \times 2}{100} = \frac{20P}{100} = \frac{P}{5} \] ### Step 3: Calculate Compound Interest (CI) Since the compound interest is compounded semi-annually, we need to adjust the rate and time: - The rate per half-year = \( \frac{10}{2} = 5\% \) - The number of half-years = \( 2 \times 2 = 4 \) The formula for Compound Interest is: \[ CI = P \left(1 + \frac{R}{100}\right)^n - P \] Where: - \( n = 4 \) (number of compounding periods) Substituting the values: \[ CI = P \left(1 + \frac{5}{100}\right)^4 - P = P \left(1.05^4\right) - P \] Calculating \( 1.05^4 \): \[ 1.05^4 = 1.21550625 \quad (\text{approximately } 1.2155) \] Thus, \[ CI = P \times 1.2155 - P = P(1.2155 - 1) = 0.2155P \] ### Step 4: Set Up the Equation According to the problem, the difference between the Compound Interest and Simple Interest is ₹124.05: \[ CI - SI = 124.05 \] Substituting the values of CI and SI: \[ 0.2155P - \frac{P}{5} = 124.05 \] ### Step 5: Simplify the Equation Convert \( \frac{P}{5} \) to a decimal: \[ \frac{P}{5} = 0.2P \] Now the equation becomes: \[ 0.2155P - 0.2P = 124.05 \] \[ 0.0155P = 124.05 \] ### Step 6: Solve for P To find \( P \), divide both sides by \( 0.0155 \): \[ P = \frac{124.05}{0.0155} \approx 8000 \] ### Conclusion The principal sum \( P \) is ₹8000. ---
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