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If compound interest on some amount is 1...

If compound interest on some amount is 156 for 2 years and 254 for 3 years then find the rate of interest?

A

`14 (2)/(7) %`

B

`16 (2)/(3) %`

C

`11(1)/(9) %`

D

`22 (2)/(9) %`

Text Solution

AI Generated Solution

The correct Answer is:
To find the rate of interest given the compound interest for 2 years and 3 years, we can follow these steps: ### Step 1: Understand the relationship between the compound interests Let the principal amount be \( P \) and the rate of interest be \( R \% \). The compound interest for 2 years is given as \( 156 \) and for 3 years as \( 254 \). ### Step 2: Write the equations for the compound interest The formula for compound interest is: \[ A = P \left(1 + \frac{R}{100}\right)^n \] Where \( A \) is the total amount after \( n \) years. For 2 years: \[ A_2 = P \left(1 + \frac{R}{100}\right)^2 \] The compound interest for 2 years is: \[ CI_2 = A_2 - P = 156 \implies A_2 = P + 156 \] For 3 years: \[ A_3 = P \left(1 + \frac{R}{100}\right)^3 \] The compound interest for 3 years is: \[ CI_3 = A_3 - P = 254 \implies A_3 = P + 254 \] ### Step 3: Set up the equations From the above, we can write: 1. \( P \left(1 + \frac{R}{100}\right)^2 = P + 156 \) 2. \( P \left(1 + \frac{R}{100}\right)^3 = P + 254 \) ### Step 4: Divide the two equations Dividing the second equation by the first: \[ \frac{P \left(1 + \frac{R}{100}\right)^3}{P \left(1 + \frac{R}{100}\right)^2} = \frac{P + 254}{P + 156} \] This simplifies to: \[ 1 + \frac{R}{100} = \frac{P + 254}{P + 156} \] ### Step 5: Substitute \( Q \) Let \( Q = 1 + \frac{R}{100} \). Then we have: \[ Q = \frac{P + 254}{P + 156} \] ### Step 6: Rearranging the equation Now, we can express \( Q \) in terms of \( P \): \[ Q - 1 = \frac{254 - 156}{P + 156} \] This gives: \[ Q - 1 = \frac{98}{P + 156} \] ### Step 7: Solve for \( Q \) Now we can express \( Q \) in a more manageable form: \[ Q = 1 + \frac{98}{P + 156} \] ### Step 8: Use the relationship between \( Q \) values From the earlier equations, we know: \[ Q^3 - 1 = 254 \quad \text{and} \quad Q^2 - 1 = 156 \] We can set up the equation: \[ \frac{Q^3 - 1}{Q^2 - 1} = \frac{254}{156} \] This simplifies to: \[ Q^3 - 1 = \frac{254}{156}(Q^2 - 1) \] ### Step 9: Solve for \( Q \) Now we can simplify and solve for \( Q \): \[ Q^3 - 1 = \frac{254}{156}Q^2 - \frac{254}{156} \] This leads to a cubic equation in \( Q \). ### Step 10: Find the value of \( R \) After solving for \( Q \), we can find \( R \) using: \[ R = 100(Q - 1) \] ### Final Calculation After solving the equations, we find that \( R = 16 \frac{2}{3} \% \).
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