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₹4,800 amounts to ₹6,000 after 4 years i...

₹4,800 amounts to ₹6,000 after 4 years if compounded annually. Find out the amount after 12 years at the same rate of interest. |

A

₹ 1,000

B

₹9,375

C

₹9,500

D

₹9,000

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to find the rate of interest first and then use it to calculate the amount after 12 years. ### Step 1: Identify the given values - Principal (P) = ₹4,800 - Amount after 4 years (A) = ₹6,000 - Time (T) = 4 years ### Step 2: Use the formula for compound interest The formula for the amount \( A \) in compound interest is given by: \[ A = P \left(1 + \frac{r}{100}\right)^T \] Where \( r \) is the rate of interest. ### Step 3: Substitute the known values into the formula Substituting the known values into the formula, we get: \[ 6000 = 4800 \left(1 + \frac{r}{100}\right)^4 \] ### Step 4: Divide both sides by 4800 \[ \frac{6000}{4800} = \left(1 + \frac{r}{100}\right)^4 \] Calculating the left side: \[ \frac{6000}{4800} = 1.25 \] So, we have: \[ 1.25 = \left(1 + \frac{r}{100}\right)^4 \] ### Step 5: Take the fourth root of both sides To isolate \( 1 + \frac{r}{100} \), we take the fourth root: \[ 1 + \frac{r}{100} = (1.25)^{\frac{1}{4}} \] ### Step 6: Calculate \( (1.25)^{\frac{1}{4}} \) Using a calculator, we find: \[ (1.25)^{\frac{1}{4}} \approx 1.0574 \] So, we have: \[ 1 + \frac{r}{100} \approx 1.0574 \] ### Step 7: Solve for \( r \) Subtract 1 from both sides: \[ \frac{r}{100} \approx 0.0574 \] Multiply by 100 to find \( r \): \[ r \approx 5.74\% \] ### Step 8: Calculate the amount after 12 years Now we need to find the amount after 12 years using the same rate of interest. We use the formula again: \[ A = P \left(1 + \frac{r}{100}\right)^T \] Where \( T = 12 \) years: \[ A = 4800 \left(1 + \frac{5.74}{100}\right)^{12} \] This simplifies to: \[ A = 4800 \left(1.0574\right)^{12} \] ### Step 9: Calculate \( (1.0574)^{12} \) Using a calculator: \[ (1.0574)^{12} \approx 1.7493 \] So, we have: \[ A \approx 4800 \times 1.7493 \approx 8396.04 \] ### Step 10: Round off the final amount The final amount after 12 years is approximately: \[ A \approx ₹8396.04 \] ### Final Answer The amount after 12 years at the same rate of interest is approximately ₹8396. ---
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