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A man buy a scooty & paid a cash dawn pa...

A man buy a scooty & paid a cash dawn pay ment for 12,000 & he promise to shopkeeper that he will pay₹ 13,050 after one year and ₹ 23,490 after 2 years at the rate of `12(1)/(2)% `of C.I. Find the amount.

A

₹41,520

B

₹43,160

C

₹42,160

D

₹41,000

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The correct Answer is:
To solve the problem step by step, we will follow these calculations: ### Step 1: Understand the Problem A man buys a scooty and makes a down payment of ₹12,000. He promises to pay ₹13,050 after one year and ₹23,490 after two years at a compound interest rate of 12.5% (which is equivalent to \( \frac{1}{8} \)). ### Step 2: Define the Total Amount Let the total amount (cost of the scooty) be \( X \). ### Step 3: Calculate the Remaining Amount After Down Payment After paying ₹12,000, the remaining amount to be paid is: \[ X - 12000 \] ### Step 4: Calculate the Amount After One Year The amount remaining after one year, considering the interest, is given by: \[ \text{Amount after 1 year} = (X - 12000) \times \left(1 + \frac{12.5}{100}\right) = (X - 12000) \times \frac{9}{8} \] ### Step 5: Subtract the First Payment After one year, he pays ₹13,050, so we have: \[ \text{Remaining amount after first payment} = (X - 12000) \times \frac{9}{8} - 13050 \] ### Step 6: Calculate the Amount After Second Year This remaining amount will again accrue interest for one more year: \[ \text{Amount after 2 years} = \left((X - 12000) \times \frac{9}{8} - 13050\right) \times \left(1 + \frac{12.5}{100}\right) = \left((X - 12000) \times \frac{9}{8} - 13050\right) \times \frac{9}{8} \] ### Step 7: Set the Equation for the Second Payment This amount should equal the second payment of ₹23,490: \[ \left((X - 12000) \times \frac{9}{8} - 13050\right) \times \frac{9}{8} = 23490 \] ### Step 8: Simplify the Equation Now, we will simplify the equation: 1. Multiply both sides by 8 to eliminate the fraction: \[ 9 \left((X - 12000) \times \frac{9}{8} - 13050\right) = 23490 \times 8 \] \[ 9 \left((X - 12000) \times 9 - 104400\right) = 187920 \] 2. Divide both sides by 9: \[ (X - 12000) \times 9 - 104400 = 20880 \] 3. Rearranging gives: \[ (X - 12000) \times 9 = 20880 + 104400 \] \[ (X - 12000) \times 9 = 125280 \] 4. Divide by 9: \[ X - 12000 = \frac{125280}{9} = 13920 \] 5. Finally, add ₹12,000 to both sides to find \( X \): \[ X = 13920 + 12000 = 25920 \] ### Conclusion The total amount (cost of the scooty) is ₹25,920. ---
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