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If x = 2 + sqrt3, then the value of (x ^...

If `x = 2 + sqrt3,` then the value of `(x ^(2)-x + 1)/(x ^(2) + x + 1) ` is

A

`2//3`

B

`3//4`

C

`4//5`

D

`3//5`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of the expression \(\frac{x^2 - x + 1}{x^2 + x + 1}\) given that \(x = 2 + \sqrt{3}\). ### Step-by-Step Solution: 1. **Substituting the value of \(x\)**: We start by substituting \(x = 2 + \sqrt{3}\) into the expression: \[ \frac{(2 + \sqrt{3})^2 - (2 + \sqrt{3}) + 1}{(2 + \sqrt{3})^2 + (2 + \sqrt{3}) + 1} \] 2. **Calculating \(x^2\)**: First, we calculate \(x^2\): \[ x^2 = (2 + \sqrt{3})^2 = 4 + 4\sqrt{3} + 3 = 7 + 4\sqrt{3} \] 3. **Substituting \(x^2\) into the expression**: Now we substitute \(x^2\) back into the expression: \[ \frac{(7 + 4\sqrt{3}) - (2 + \sqrt{3}) + 1}{(7 + 4\sqrt{3}) + (2 + \sqrt{3}) + 1} \] 4. **Simplifying the numerator**: Simplifying the numerator: \[ 7 + 4\sqrt{3} - 2 - \sqrt{3} + 1 = 6 + 3\sqrt{3} \] 5. **Simplifying the denominator**: Now simplifying the denominator: \[ 7 + 4\sqrt{3} + 2 + \sqrt{3} + 1 = 10 + 5\sqrt{3} \] 6. **Final expression**: We now have: \[ \frac{6 + 3\sqrt{3}}{10 + 5\sqrt{3}} \] 7. **Rationalizing the denominator**: To simplify further, we multiply the numerator and denominator by the conjugate of the denominator: \[ \frac{(6 + 3\sqrt{3})(10 - 5\sqrt{3})}{(10 + 5\sqrt{3})(10 - 5\sqrt{3})} \] 8. **Calculating the denominator**: The denominator becomes: \[ 10^2 - (5\sqrt{3})^2 = 100 - 75 = 25 \] 9. **Calculating the numerator**: The numerator expands as follows: \[ (6 \cdot 10) + (6 \cdot -5\sqrt{3}) + (3\sqrt{3} \cdot 10) + (3\sqrt{3} \cdot -5\sqrt{3}) = 60 - 30\sqrt{3} + 30\sqrt{3} - 45 = 15 \] 10. **Final result**: Thus, we have: \[ \frac{15}{25} = \frac{3}{5} \] ### Final Answer: The value of \(\frac{x^2 - x + 1}{x^2 + x + 1}\) is \(\frac{3}{5}\).
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MOTHERS-ALGEBRA -MULTIPLE CHOICE QUESTION
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