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Let x= root(6)(27)- sqrt(6 3/4) and y= (...

Let `x= root(6)(27)- sqrt(6 3/4)` and `y= (sqrt 45+ sqrt 605+ sqrt 245)/(sqrt 80+sqrt 125)`, then the value of `x^2+y^2` is:
मान लीजिये कि `x= root(6)(27)- sqrt(6 3/4)` और `y= (sqrt 45+ sqrt 605+ sqrt 245)/(sqrt 80+sqrt 125)` है, तो `x^2+y^2` का मान ज्ञात करें |

A

`(223)/(36)`

B

`(221)/(36)`

C

`(221)/(9)`

D

`(227)/(9)`

Text Solution

Verified by Experts

The correct Answer is:
A
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