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Find the two numbers whose LCM is 78 and...

Find the two numbers whose LCM is 78 and HCF is 13?

A

58 and 13 or 16 and 29

B

68 and 23 or 36 and 49

C

18 and 73 or 56 and 93

D

78 and 13 or 26 and 39

Text Solution

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The correct Answer is:
To find the two numbers whose LCM is 78 and HCF is 13, we can follow these steps: ### Step 1: Use the relationship between LCM, HCF, and the two numbers We know that the product of the two numbers (let's call them \( a \) and \( b \)) is equal to the product of their LCM and HCF. This can be expressed as: \[ a \times b = \text{LCM}(a, b) \times \text{HCF}(a, b) \] Substituting the given values: \[ a \times b = 78 \times 13 \] ### Step 2: Calculate the product Now, let's calculate \( 78 \times 13 \): \[ 78 \times 13 = 1014 \] So, we have: \[ a \times b = 1014 \] ### Step 3: Prime factorization of the product Next, we will perform the prime factorization of 1014 to help us find the two numbers: \[ 1014 = 2 \times 3 \times 13 \times 13 \] This can also be written as: \[ 1014 = 2 \times 3 \times 13^2 \] ### Step 4: Identify the common factor Since we know that the HCF of \( a \) and \( b \) is 13, we can express \( a \) and \( b \) in terms of their common factor: Let: \[ a = 13m \quad \text{and} \quad b = 13n \] where \( m \) and \( n \) are co-prime (i.e., HCF(m, n) = 1). ### Step 5: Substitute and simplify Now substituting \( a \) and \( b \) into the product: \[ (13m) \times (13n) = 1014 \] This simplifies to: \[ 169mn = 1014 \] Dividing both sides by 169 gives: \[ mn = \frac{1014}{169} = 6 \] ### Step 6: Find pairs of \( m \) and \( n \) Now we need to find pairs of \( m \) and \( n \) such that their product is 6. The pairs of factors of 6 are: 1. \( (1, 6) \) 2. \( (2, 3) \) ### Step 7: Calculate \( a \) and \( b \) Now we can find the corresponding values of \( a \) and \( b \): 1. For \( (m, n) = (1, 6) \): \[ a = 13 \times 1 = 13, \quad b = 13 \times 6 = 78 \] 2. For \( (m, n) = (2, 3) \): \[ a = 13 \times 2 = 26, \quad b = 13 \times 3 = 39 \] ### Final Result Thus, the two pairs of numbers whose LCM is 78 and HCF is 13 are: 1. \( (13, 78) \) 2. \( (26, 39) \)
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