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A milk seller has three types 403,465 an...

A milk seller has three types 403,465 and 496 gallon of milk. Find the minimum number of bottles, which can measure the whole quantity of milk without mixing them ?

A

34

B

46

C

26

D

44

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the minimum number of bottles that can measure the whole quantity of milk without mixing them, we will follow these steps: ### Step 1: Identify the quantities of milk The quantities of milk given are: - 403 gallons - 465 gallons - 496 gallons ### Step 2: Find the Highest Common Factor (HCF) To find the HCF of the three quantities, we will factor each number: 1. **Factor 403**: - 403 can be factored as \(13 \times 31\). 2. **Factor 465**: - 465 can be factored as \(15 \times 31\) (or \(3 \times 5 \times 31\)). 3. **Factor 496**: - 496 can be factored as \(16 \times 31\) (or \(2^4 \times 31\)). From the factorizations, we can see that the common factor among all three quantities is \(31\). ### Step 3: Calculate the HCF Thus, the HCF of 403, 465, and 496 is: \[ \text{HCF} = 31 \] ### Step 4: Determine the number of bottles for each type of milk Now, we will calculate how many bottles of 31 gallons are needed for each quantity of milk: 1. **For 403 gallons**: \[ \text{Number of bottles} = \frac{403}{31} = 13 \] 2. **For 465 gallons**: \[ \text{Number of bottles} = \frac{465}{31} = 15 \] 3. **For 496 gallons**: \[ \text{Number of bottles} = \frac{496}{31} = 16 \] ### Step 5: Calculate the total number of bottles Now, we sum the number of bottles required for each type of milk: \[ \text{Total number of bottles} = 13 + 15 + 16 = 44 \] ### Final Answer The minimum number of bottles required to measure the whole quantity of milk without mixing them is: \[ \boxed{44} \] ---
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