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Three pieces of cakes of weights 4 1/2 l...

Three pieces of cakes of weights `4 1/2 lbs, 6 3/4 lbs` and `7 1/5 lbs` respectively are to be divided into parts of equal weights. Further, each must be as heavy as possible. If one such part is served to each guest, then what is the maximum number of guests that could be entertained?

A

54

B

72

C

20

D

41

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • Solve the following problems independently of each other Once, Amey and his friends decided to celebrate their success after they secured their admissions into various IIMs(Indian Institues of Management). They ordered a thin crust cheese pizza from Pizza Hut and they told pizza hut to deliver it without cutting into pieces. The pizza was larger enough to satiate their carvings. Once they receive the pizza, they were so excited that they didn't mind cutting the pizza into any shape and size. However, while cutting the pizza they cut it from edge to edge, that is they started from any point on the circumference and didn't lift the knife until it reaches another point on the circumference and didn't lift the knife until it reaches another point on the circumferences. It's like they cut along various chords of a circle. Amey had just made 7 cuts making maximum possible number of pieces such that everyone present there could have had one piece each.But before anybody could have picked up a piece of it few more friends arrived at the party. Thus to serve the new guests at his party, he made one more cut keeping in mind that each new guest would get exactly one piece of pizza. what 's the maximum number of new guests (friends) that showed up at the party?

    A
    5760
    B
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    C
    576000
    D
    5760000

  • Three sides of a trapezium are each equal to 6 cm. Let a in (0,pi/2) be the angle beetween a part of adjacent sides. If the area of the trapezium is the maximum possible, then what is a a equal to?

    A
    A)`pi/6`
    B
    B)`pi/4`
    C
    C)`pi/3`
    D
    D)`(2pi)/5`

  • The least number which when divided by 2, 3, 4, 5 and 6 leaves the remainder 1 in each case. If the same number is divided by 7 it leaves no remainder. The number is :

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    231
    B
    301
    C
    371
    D
    441

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