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The HCF of is 4/15, 6/25and16/25...

The HCF of is 4/15, 6/25and16/25

A

`(2)/(75)`

B

`(16)/(5)`

C

`(6)/(25)`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the HCF (Highest Common Factor) of the fractions \( \frac{4}{15}, \frac{6}{25}, \frac{16}{25} \), we follow these steps: ### Step 1: Identify the Numerators and Denominators We will first separate the numerators and denominators of the given fractions: - Numerators: 4, 6, 16 - Denominators: 15, 25, 25 ### Step 2: Find the HCF of the Numerators Next, we need to find the HCF of the numerators (4, 6, and 16). - The factors of 4 are: 1, 2, 4 - The factors of 6 are: 1, 2, 3, 6 - The factors of 16 are: 1, 2, 4, 8, 16 The common factors are: 1, 2. The highest of these is 2. Thus, HCF of the numerators = 2. ### Step 3: Find the LCM of the Denominators Now, we will find the LCM of the denominators (15, 25, and 25). - The prime factorization of 15 is \( 3 \times 5 \). - The prime factorization of 25 is \( 5^2 \). To find the LCM, we take the highest power of each prime: - For 3: \( 3^1 \) - For 5: \( 5^2 \) Thus, LCM = \( 3^1 \times 5^2 = 3 \times 25 = 75 \). ### Step 4: Form the HCF of the Fractions Now that we have the HCF of the numerators and the LCM of the denominators, we can form the HCF of the fractions: \[ \text{HCF} = \frac{\text{HCF of numerators}}{\text{LCM of denominators}} = \frac{2}{75} \] ### Final Answer The HCF of the fractions \( \frac{4}{15}, \frac{6}{25}, \frac{16}{25} \) is \( \frac{2}{75} \). ---
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