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Prove the following: (sin5x + sin 3x)/(c...

Prove the following: `(sin5x + sin 3x)/(cos5x + cos3x)=tan4x`

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  • TRIGNOMETRIC FUNCTIONS

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Prove the following : (sin 5x + sin3x)/(cos 5x + cos 3x)= tan 4x .

Prove the following: (sinx + sin3x)/(cosx + cos3x)=tan 2x

Prove the following : (sinx +sin3x)/(cos x + cos 3x)= tan 2x .

Prove the following : (sin 5x -2sin 3x+sinx)/(cos 5x-cos x)= tan x .

Prove the following: (sin x -sin 3x)/(sin^2 x -cos^2 x)= 2sinx

Prove the following: cot 4x (sin 5x + sin 3x) = cot x (sin 5x -sin 3x)

Prove that: (sinx +sin3x)/(cosx+cos3x)=tan2x

Prove the following: cos 4x = 1 - 8sin^2 x cos^2 x

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JBD PUBLICATION-TRIGNOMETRIC FUNCTIONS-EXAMPLE
  1. Show tha: cos4A=1-8cos^2A+8cos^4A.

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  2. Show tha: cos6A=32cos^6A-48cos^4A+18cos^2A-1

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  3. Prove the following: (sin5x + sin 3x)/(cos5x + cos3x)=tan4x

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  4. Prove the following:sin(150^@+x)+sin(150^@-x)=cosx

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  5. Prove that sin51^(@)+cos81^(@)=cos21^(@) .

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  6. Show that: sn10^@+sin20^@+sin40^@+sin50^@=sin70^@+sin80^@

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  7. Find the principal solutions (0 le x le 2pi) of the following euqtions...

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  8. Find the principal solutions (0 le x le 2pi) of the following euqtions...

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  9. Find the principal and general solutions of the following equation:- t...

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  10. Find the principal and general solutions of the following equation:- s...

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  11. Find the general solution of the following equations: cos 4 x = cos 2x

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  12. Find the general solutions of the equations sinx+sin3x+sin5x=0.

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  13. Find the general solution of the following equations: cos 4 x = cos 2x

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  14. An athlete runs 4 times around a circular running a path to describe 1...

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  15. Prove that: cot^2frac (pi)(6)+cosecfrac (5pi)(6)+3tan^2frac (pi)(6)=6

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  16. In triangleABC, prove that cos(A+B)+cosC=0

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  17. In triangleABC, prove that cos((A+B)/(2))=sinC/2

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  18. Prove the following: cos((3pi)/2+x)cos(2pi+x)[cot((3pi)/2-x)+cot(2pi+x...

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  19. If tan alpha= (m)/(m+1) and tan beta=(1)/(2m+1), the find the value o...

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  20. If tan(alpha+theta)=ntan(alpha-theta), show that:(n+1)sin 2theta=(n-1)...

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