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If [(1-i)/(1+i)]^100 = a+ib then the pos...

If `[(1-i)/(1+i)]^100 = a+ib` then the possible values of a and b are:

A

a=0, b=1

B

a=1, b=0

C

a=2, b=-1

D

none of these

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  • If ((1-i)/(1+i))^(100)=a+ib , than

    A
    `a= 2,b=-1`
    B
    `a = 1, b = 0`
    C
    `a= 0,b=1`
    D
    `a=-1, b = 2`.

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