A container of volume `V L` contains an equilibrium mixture that consists of `2` mol each of gaseous `PCl_(5), Pcl_(3)` and `Cl_(2)` at `3` atm `T K`. Some `Cl_(2)` is added unitl the volume is double keeping `P` and `T` constant. Calculate moles of `Cl_(2)` added and `K_(p)` for `PCl_(5) rarr PCl_(3)+Cl_(2)`

According to Le Chatelier's principle, on applying any external force to desturb equilibrium, the reaction moves in that direction in which effect of exteranal force is minimised as far as possible. A container whose volume is V contains an equilibrium mixture that contains 2 moles each of PCl_(5) , PCl_(3) and Cl_(2) n (all gases). The pressure is 3atm and temperature is T. A certain amount of Cl_(2)(g) is now introduced keeping the pressure and temperature constant untill the equilbrium volume changes to 2 V. PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g) . The moles Cl_(2) that was added is :

According to Le Chatelier's principle, on applying any external force to desturb equilibrium, the reaction moves in that direction in which effect of exteranal force is minimised as far as possible. A container whose volume is V contains an equilibrium mixture that contains 2 moles each of PCl_(5) , PCl_(3) and Cl_(2) n (all gases). The pressure is 3atm and temperature is T. A certain amount of Cl_(2)(g) is now introduced keeping the pressure and temperature constant untill the equilbrium volume changes to 2 V. PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g) . The equilibrium constant K of the reaction :

A container whose volume is V contains an equilibrium mixture that consists of 2 mol each of PCl_5, PCl_3 and Cl_2 (all as gases) . The pressure is 30.3975 kpa and temperature is T. A certain amount of Cl_2 (g) is now introduced keeping the pressure and temperature constant until the equilibrium volume is 2V. Calculate the amount of Cl_2 that was added and the value of k_p .

How much PCl_(5) must be added to a one litre vessel at 250^(@)C in order to obtain a 35 concentration of 0.1 mol of Cl_(2) ? K_(c) for PCl_(5) hArr PCl_(3)+Cl_(2) is 0.0414 mol L^(-1)

How much PCl_(5) must be added to a one litre vesel at 250^(@)C in order to obtain concentration of 0.1 mole of Cl_(2) at equilibrium K_(C) for PCl_(5)(g) hArr PCl_(3(g)+Cl_(2) is 0.0414M

PCl_(3), PCl_(3) and Cl_(2) are at eqilibrium at 500 K and above have concentration 1.59 M for PCl_(3), 1.59 M for Cl_(2) and 1.41 M for PCl_(5). Calculate K_(c) for the reaction : PCl_(5) hArr PCl_(3) + Cl_(2)

Calculate percentage change in M_(avg) of the mixture, if PCl_(5) undergo 50% decomposition. PCl_(5) rArr PCl_(3) + Cl_(2)

PCl_(5), PCl_(3) and Cl_(2) are at equilibrium at 500 K and having concentration 1.59 M PCl_(3), 1.59 M Cl_(2) and 1.41 M PCl_(5) . Calculate K_(c) for the reaction, PCl_(5) hArr PCl_(3) + Cl_(2)