The force `F= (2 + 4x^2 + 2x^3)` N acting on a body displaces from zero to 5m. Calcilate the total work done by the force .

Certain force acting on a 20 kg mass changes its velocity from 5ms ^-1 to 2ms^-1 . Calculate the work done by the force.

A particle acted on by two forces 4 hat i+ 3 hat j and 3 hat i+ 2 hat j is displaced from the point hat i+ 2 hat j to 5 hat i+ 4 hat j . Find the totral work done by these forces.

When a person lift a body from the ground,work done by the lifting force is :

A horizontal force acts on a body placed on a smooth horizontal table . If the force applied is 10N,find the total work done when the displacement of body is 5m.​

forces of magnitudes 5,3,1 units acting in the direction 6hati+2hatj+3hatk,3hati-2hatj+6hatk,2hati-3hatj-6hatk respectively act on a particle, which is displaced from the point (2,-1,-3) to (5,-1,1). Find the work done by the forces.

A block is pushed by a force F = 10 N. A frictional force of 2 N acts between the block and the surface. Find the work done by the friction when the block moves 10 m.

In each of the following a force,F is acting on an object of mass,m. The direction of displacement is from west to east shown by the longer arrow. Observe the diagrams carefully and state whether the work done by the force is negative,positive or zero.