A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction = 0.1. Compute the:- work done by friction in 10 s.

A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction = 0.1. Compute the:- work done by the net force on the body in 10 s.

A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction = 0.1. Compute the:- work done by the applied force in 10 s.

A body of mass 10 kg at rest was moved by a constant force 50 N. Find the K.E. of the body at the end of 5 seconds.

A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7N on a table with coefficient of kinetic friction = 0.1. Comput the a) work done by the applied force in 10s, b) work done by friction in 10 s, c) work done by the net force on the body 10s, d) change in kinetic energy of the body in 10s. Interpret your result.

If under the action of variable force overset rarr F ,a body is displaced by overset rarr S ,the work done is given by:

A force acting on a 10 kg mass changes its velocity form 54 km/h to 90 km/h. Calculatethe work done by the force.

Certain force acting on a 20 kg mass changes its velocity from 5ms ^-1 to 2ms^-1 . Calculate the work done by the force.

What is the force acting on a body of mass 25 kg moving with constant velocity 10 m s^(-1) ?

Forces vecF=hati+2hatj+hatk acts on a particle and displaced from the point (2,1,1) to point (3,2,4) Find the work done by force vecF .